Utilizing metal louvers requires (120 in 2/.75 = 160 in 2) to obtain 120 in 2 of free area.Ĭonfirmation: 75% of 160 in 2 =. (120,000 BTU / 1,000) x 1 in 2 = 120 in 2 minimum free area for each of the required (2) openings (Total BTU Input of all Appliances / 1,000 = Free Area of Each Opening Required ) The minimum free area of 1 square inch per 1,000 Btu/h of the total input rating of all appliances in the (120,000 BTU / 1,000) x 50 ft 3 = 6,000 ft 3 Combustion Air Supplied From Same Story: ( (Total BTU Input of all Appliances / 1,000) x 50 = Volume Required The minimum required volume shall be 50 cubic feet per 1,000 Btu/h of the appliance Furnace 80,000 BTU + Water Heater 40,000 BTU = 120,000 BTU Total Minimum Indoor Air Communicating with the Appliances:
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